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adpcm dequantization problem, where does step_size/8 come from?
lhat
post Dec 27 2011, 11:05
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I just started learning adpcm.

From the link below

http://wiki.multimedia.cx/index.php?title=IMA_ADPCM

diff = ((signed)nibble + 0.5) * step / 4,
^^

= (signed)( nibble[2] * step + nibble[1]*step/2 + nibble[0]*step/4 + step/8)
^^^^
the term step/8 is not exist in the quatization process.

isn't the dequantization the inverse of quatization?

what's the reason for adding step/8

and what will happen if I ignore the step/8 in dequantization step?

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