
What I conclude from this image is that the stereo separation of the rear channels is stronger than the stereo separation of the front channels. This means I have to mix the front channels differently into the stereo channels than the rear channels.
There are two extreme points that a speaker can have. It can be located at 0° (like the center channel). In that case the channel should go equally to the left and right channel. Or it can be located at ±90°, which means that 100% of the channel goes either to the left or to the right.
The front channels are positioned 30° from the 0° point, so the calculation would be as follows:
Front: 30° / 90° * 50 + 50 = 67%
So 67% of the channel goes to the same side, while the rest (33%) goes to the other side.
The calculation for the rear channels is similar:
Rear: 70° / 90° * 50 + 50 = 89%
So 89% of the channel goes to the same side, while the rest (11%) goes to the other side.
But then I noticed that this would be suitable for headphones but not for speakers. So I decided to set 70° as the maximum and not 90°:
Front: 30° / 70° * 50 + 50 = 71% (other side: 29%)
Rear: 70° / 70° * 50 + 50 = 100% (other side: 0%)
This way I have the widest possible stereo separation while maintaining the separation ratio between front and rear. But I still feel that it's just a compromise and not an ideal solution.
Then something else came to my mind. I noticed that most applications don't mix the center channel 50%/50% into the stereo channels but 71%/71% (-3.01dB = square root of 2, divided by 2). So, aren't two speakers with half the amplitude as loud as one speaker? If I should indeed use 71% instead of 50% I wonder how I have to apply this to the other channels.
