QUOTE (d_headshot @ Aug 6 2009, 10:51)

I was supposed to be asking if the speed of the preset had any negative effect on the quality. I also should have mentioned my question stemmed from foobar2000's option for the tickbox with "--vbr-new". If I'm using the 3.98.2 encoder and I leave that unticked, it does it anyways because it's the default?
Yes I think it will use --vbr-new anyway as it's the default. If you want to force it to use the older --vbr-old I think you'd have to set a custom converter profile for it (click "add new" and then select "custom" for the encoder in the foobar converter options section.)
As for the "fast" reference I think that this came about because it was faster than the old vbr algorithm so in the old "--preset" method of vbr quality selection they used the modifier "fast" to specify it's use. For example "--preset standard" used the old vbr algorithm whereas "--preset fast standard" used the new vbr algorithm though each still targeted the same "standard" vbr quality. Lately the "--preset" method of specifying vbr target quality has been replaced with the simpler "-Vx" method, so for example the old "--preset standard" would be equivalent to "-V2 --vbr-old" and "--preset fast standard" would be equivalent to "-V2 --vbr-new" or more simply just "-V2" as the --vbr-new is now the default.
As for the original question as to what "fast" mode (as per the meaning --vbr-new) does. It controls the part of the encoding algorithm that selects what bit rate is required to encode a given frame to achieve the targeted quality level. You should
not think of "--vbr-new" as faster but lower quality version of "--vbr-old" but rather as a completely new algorithm which just happens to run a little faster than the older algorithm.